Solve the problem.A holder of a $34,800, 9%, 120-day note dated June 3 decides to sell the note at a discount based on ordinary interest. The note is sold on July 15 at a discount of 12% using the banker's rule. Find the proceeds.
A. $34,912.06
B. $34,900.11
C. $35,145.04
D. $34,556.16
Answer: A
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Provide an appropriate response.A surveyor starts at point A on a triangular piece of land and determines angle A and the two sides AB and AC as shown. Find angle B to the nearest 0.1°. 
A. 69.8° B. 154.8° C. 25.2° D. 85.3°
Use the trapezoidal rule and Simpson's rule to approximate the value of the definite integral.
?
?
A. By trapezoidal rule 1.1325, by Simpson's rule 0.6554 B. By trapezoidal rule 1.9565, by Simpson's rule 0.6555 C. By trapezoidal rule 0.6572, by Simpson's rule 0.6551 D. By trapezoidal rule 1.6290, by Simpson's rule 1.6108 E. By trapezoidal rule 1.5807, by Simpson's rule 0.6533
Simplify.
A. - 
B. 0
C. ± 
D. 
Solve for x. Check your answers.10 - 13 + 9 = 7 + x - 4
A. x = -5 B. x = 17 C. x = 3 D. x = 35