Solve the differential equation subject to the initial conditions.
+ xy = 2x; y = -6 when x = 0
A. y = 2e-x2/2 - 8
B. y = 2ex2/2 - 8
C. y = -8e-x2/2 + 2
D. y = -8ex2/2 + 2
Answer: C
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A. x = 
arcsin 
B. x = 
arcsin 
C. x = 
arcsin 
D. x = 
arcsin 
Solve the problem.The stretch in a loaded spring varies with the load it supports. If the spring stretches 6 cm for every pound of load added, find the distance in centimeters that the spring has stretched when 7 pounds are added.
A. 7 cm B. 42 cm C. 13 cm D. -1 cm
Graph the equation.(x - 5)2 + (y + 3)2 = 4
A. 
B. 
C. 
D. 
Solve the problem. Round your answer to two decimal places.Hooke's Law for an elastic spring states that the distance a spring stretches variesdirectly as the force applied. If a force of 25 pounds stretches a certain spring 
then how much will a force of 
stretch the spring?
A. 3 in. B. 175 in. C. 2 in. D. 21 in.