Solve the problem.A simple electrical circuit consists of a resistor connected between the terminals of a battery. The voltage V (in volts) is dropping as the battery wears out. At the same time, the resistance R (in ohms) is increasing as the resistor heats up. The power P (in watts) dissipated by the circuit is given by P =
. Use the equation
=
+
src="https://sciemce.com/media/4/ppg__as0611191936__f1q230g5.jpg" style="vertical-align: -17.0px;" /> to find how much the power is changing at the instant when R = 2 ohms, V = 2 volts,
and dV/dt = -0.02 volts/sec.
A. -0.09 watts
B. -0.01 watts
C. 0.01 watts
D. 0.09 watts
Answer: A
You might also like to view...
Solve the initial value problem for y as a function of x.x
= 1, x > 8, y(16) = 0
A. y = sec-1
B. y = sin-1
+
C. y = sec-1 -
D. y = sec-1
-
Find the distance d(P1, P2) between the points P1and P2.P1 = (-6, -4); P2 = (6, 4)
A. 4
B. 80
C. 4
D. 80
Find the zeros of the polynomial function and state the multiplicity of each.f(x) = x3 + 5x2 - x - 5
A. -5, multiplicity 2; 1, multiplicity 1 B. -1, multiplicity 1; 1, multiplicity 1; 5, multiplicity 1 C. -5, multiplicity 1; -1, multiplicity 2 D. -5, multiplicity 1; -1, multiplicity 1; 1, multiplicity 1
If a triangle has vertices of
and
then the area of the triangle is given by
Find the area of the triangle with vertices at the given points.(-4, -4) (1, 4) (4, 2)
A. 34 B. 52 C. 26 D. 17