Club mosses
(a) are placed in the subphylum Pterophyta.
(b) are so-called because of the social nature of the plants.
(c) do not produce gametophytes.
(d) are so-called because most produce strobili.
(d) are so-called because most produce strobili.
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Which of the following explains how genetic variation in a population of bacteria results from this process?
(A) Bacterial proteins transferred from the donor bacterium by the phage to the recipient bacterium recombine with genes on the recipient's chromosome. (B) The recipient bacterium incorporates the transduced genetic material coding for phage proteins into its chromosome and synthesizes the corresponding proteins. (C) The phage infection of the recipient bacterium and the introduction of DNA carried by the phage cause increased random point mutations of the bacterial chromosome. (D) DNA of the recipient bacterial chromosome undergoes recombination with DNA introduced by the phage from the donor bacterium, leading to a change in the recipient's genotype.
Color blindness is an X-linked recessive trait. Two normal-vision parents produce a color-blind child. The child's sex is _____________.
Fill in the blank(s) with the appropriate word(s).
When bacteria are inoculated into a new sterile nutrient broth, their numbers don't begin to increase immediately. Instead, there is a lag phase that may last for an hour or even several days. Why don't bacterial numbers increase immediately?
a. There are not enough nutrients for the bacteria to grow, and growth is delayed until there are some dead cells to cannibalize. b. The bacteria have to establish a biofilm before their numbers can increase. c. The bacteria must adjust to the nutrient content in the new medium, synthesizing necessary amino acids, growth factors, and enzymes. d. The medium contains inhibitors that prohibit rapid growth of the bacteria, and these must be inactivated before bacterial numbers will increase.
A DNA microarray (also called a DNA chip) can be used to ________
A) detect mutations that may indicate a risk of disease B) detect RFLPs C) generate mutations in the gene of interest D) determine protein translation levels