Express as a sum of logarithms.log6(228 ? 255)
A. log66 + log228228 + log255255
B. log658,140 + log658,140
C. log2286 + log2556
D. log6228 + log6255
Answer: D
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Provide an appropriate response.The area under the standard normal curve between 1 and 2 is equal to 0.1359. Scores on a particular aptitude test are normally distributed with a mean of 100 and a standard deviation of 10. Which of the following are equal to 13.59%?a. The percentage of scores between 120 and 130b. The percentage of scores between 110 and 120c. The percentage of scores between 80 and 90d. The percentage of scores between 90 and 120
A. a B. d C. b D. b, c E. a, b
Apply the distributive property.-3x2(-8x + 5)
A. -24x3 - 15x2 B. 24x3 - 15x2 C. 24x3 + 15x2 D. -24x3 + 15x2
Find the area under the curve over the indicated interval.
y = 6/x; [1,4] What will be an ideal response?
Solve the system of linear equations. x + 8y = 4-3x + 9y = -12
A. (5, -1) B. (4, 0) C. (5, 4) D. No solutions