Determine the void ratio of a soil if its bulk density is 125 lb/ft3 and it has a moisture content of 24 percent. The specific gravity of the soil particles is 2.75. Also, determine its dry density and degree of saturation.
What will be an ideal response?
Solve for ?d, dry density, using Equation 17.11.
?d = ? / (1 + w)
?d = 125 / (1 + 0.24)
?d = 100.81 lb/ft3
Solve for void ratio, e, using Equation 17.13. This equation can be modified to
use dry density when the degree of saturation is zero (no moisture is present) as
follows:
?d = (Gs ?w) / 1 + e
1 + e = Gs ?w / ?d
e = (Gs ?w / ?d) – 1
e = ((2.75)(62.4) / 100.81) – 1
e = 0.702
Solve for the degree of saturation, S.
S = w Gs / e
S = (0.24)(2.75) / 0.702
S = 0.940
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