Briefly describe how we can use the orbital characteristics of stars at many distances from the galactic center to determine the distribution of mass in the Milky Way
What will be an ideal response?
Using the orbital velocity law, related to Newton's version of Kepler's third law, we can determine the mass of the galaxy that lies within a particular orbit (and thus distance from the center) if we know the average orbital velocity of stars or clouds at that distance. Therefore, by applying the orbital velocity law to the orbits of stars at many distances from the galactic center, we can determine how much mass lies within each radius. We often use the 21-cm line from atomic hydrogen to measure velocities of gas clouds because light at radio wavelengths can penetrate the dust that would normally obscure our vision in other wavelengths. Thus, we can measure orbital velocities of gas clouds wherever the gas is located in the galaxy.
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In the absence of air resistance, a boulder and a pebble dropped from rest will fall with equal
1) forces of gravity. 2) accelerations. 3) energies. 4) all these. The reason that this quantity is not greater for the boulder than the pebble is that 5) both the boulder and the pebble fall at the same speed. 6) the initial potential energies of each is the same. 7) gravitational force acting on each is the same. 8) the greater gravitational force on the boulder acts on a correspondingly greater mass.
The thermosphere is warm because it
A) absorbs X-rays. B) absorbs infrared light. C) absorbs visible light. D) contains greenhouse gases. E) absorbs ultraviolet light.
Wall posters are usually sold curled up in cylindrical cardboard tubes. If the length of the tube is 84.5 cm, and the inside diameter of the tube is 2
40 cm, what is the area of the poster expressed to the correct number of significant figures? (Assume the poster is just as long as the tube and does not overlap itself.) A) 202.8 cm2 B) 637.1 cm2 C) 203 cm2 D) 319 cm2 E) 637 cm2
To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of the pole after 0.5 s and then reaches the top of the pole again after a total elapsed time of 4.1 s
How high is the pole above the point where the ball was launched? A) 10 m B) 13 m C) 16 m D) 18 m E) 26 m