A urine specimen obtained from a patient went to the microbiology lab for a bacterial culture and antibiotic sensitivity testing. The specimen sat out on the processing counter for a couple of hours before being cultured. Twenty fours hours later, the lab report goes into the computer---over 100,000 bacterial cells per milliliter of urine. Which statement is an accurate assessment of these results?
A. Urine samples have to be taken from the kidney in order to get a true bacterial count.
B. Not all bacteria will grow on bacteriological media, so the total count is grossly underestimated.
C. Urine is a sterile fluid as it leaves the body, so it is likely that the specimen was mishandled by the nursing staff when the sample was obtained.
D. The bacterial count is not accurate since the culture sat without refrigeration.
Answer: D
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The gene (IGF1) that encodes a growth hormone has one allele (IGF1-A) that is found in small dogs but not in dogs that are very large. What does this suggest about body size of small dogs?
A. Body size depends on how much growth hormone is produced during early fetal development. B. Body size depends on whether or not the IGF1-A allele is present, if it is the dog grows very large, if it is not present the dog retains a small size. C. It suggests that small dogs are small because the IGF1-A allele is expressed, perhaps inhibiting the growth of the dog and the release of growth hormone. D. It suggests that small dogs have more growth hormone released during fetal development but none released after the birthing process. E. Body size depends on nutrition, not on genetics.
A woman and her spouse both show the normal phenotype for pigmentation, but both had one parent who was an albino. Albinism is an autosomal recessive trait. What is the probability that their first child will be an albino?
A) 0 B) 1/4 C) 1/2 D) 3/4 E) 1
Which of the following sequences of events in the production of recombinant DNA are in the correct order?
A. cut DNA with restriction enzymes, mix DNA with plasmid DNA, add DNA ligase B. mix DNA with plasmid DNA, cut with restriction enzymes, add DNA ligase C. add DNA ligase, cut DNA with restriction enzymes, mix DNA with plasmid DNA D. mix DNA with plasmid DNA, add DNA ligase, cut with restriction enzymes E. cut with restriction enzymes, add DNA ligase, mix DNA with plasmid DNA
hydrogen bond
What will be an ideal response?