Use mathematical induction to prove the statement is true for all positive integers n.11 + 22 + 33 + . . . + 11n = 

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Answers may vary. Possible answer:
First, we show the statement is true when n = 1.
For n = 1, we get 11 =  
 Since  =  = 11, P1 is true and the first condition for the principle of induction is satisfied.
Next, we assume the statement holds for some unspecified natural number k. That is,
Pk  is assumed true.
On the basis of the assumption that Pk is true, we need to show that Pk+1 is true. 
Pk+1
So we assume that  is true and add the next term,  to both sides of the equation.

11 + 22 + 33 + ... + 11k + 11(k + 1) =  + 11(k + 1)
11 + 22 + 33 + ... + 11k + 11(k + 1) = 11

11 + 22 + 33 + ... + 11k + 11(k + 1) = 
The last equation says that Pk+1 is true if Pk is assumed to be true. Therefore, by the principle of mathematical induction, the statement 11 + 22 + 33 + ... + 11n =   is true for all natural numbers n.

Mathematics

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