Solve the initial value problem. = 16t(4t2 - 1)3, s(1) = -2

A. s = (4t2 - 1)4 - 83
B. s = (4t2 - 1)4 - 2
C. s = (4t2 - 1)4 - 
D. s = (4t2 - 1)4


Answer: C

Mathematics

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