Solve the initial value problem.
= 16t(4t2 - 1)3, s(1) = -2
A. s = (4t2 - 1)4 - 83
B. s = (4t2 - 1)4 - 2
C. s = (4t2 - 1)4 -
D. s = (4t2 - 1)4
Answer: C
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Perform the operation indicated. Simplify. +
A.
B.
C.
D.