A man and a woman with normal phenotypes have several children, one of whom has albinism. a. What can you conclude about the genotype of the mother? b. What is the probability that the children who do not display albinism are heterozygous?

What will be an ideal response?


(a) Both parents must be heterozygous (a carrier) in order to have an offspring with albinism.
(b) With parents of genotype Aa × Aa, the genotypes possible for offspring not displaying the traits of albinism are AA, Aa, and aA. Two of these three are carriers, so there is a (66%) chance that a child who does not display albinism is a carrier.

Biology & Microbiology

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Biology & Microbiology

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Biology & Microbiology