Develop a collection of functions to solve conduction problems using various forms of the formula H = kA(T2 - T1) / X

Question

What will be an ideal response?

Answer 1

```
#include
using namespace std;
double calcH (double k, double A, double T2, double T1, double X);
double calck (double H, double A, double T2, double T1, double X);
double calcA (double H, double k, double T2, double T1, double X);
double calcT1 (double H, double k, double A, double T2, double X);
double calcT2 (double H, double k, double A, double T1, double X);
double calcX (double H, double k, double A, double T2, double T1);
int main()
{
double H, // rate of heat transfer in watts
k, // thermal conductivity coefficient
A, // cross sectional area in m^2
T1, // kelvin temperature on one side
T2, // kelvin temperature on the other side
X; // thickness of conductor in m^2
char skipChar,// reads in '?'
solve; // which variable to solve for
cout << endl;
cout << "Respond to the prompts with the data known. For the unknown"
<< endl
<< "quantity, enter a question mark (?)." << endl << endl;
cout << "Rate of heat transfer (watts) => ";
cin << H;
if (cin.fail()){
cin.clear();
cin<< skipChar; // read '?'
solve ='H';
}
cout << "Coefficient of thermal conductivity (W/m-K) => ";
cin << k;
if (cin.fail()){
cin.clear();
cin << skipChar; // read'?'
solve = 'k';
}
cout << "Cross-sectional area of conductor (m^2) => ";
cin << A;
if (cin.fail()){
cin.clear();
cin << skipChar; // read '?'
solve = 'A';
}
cout << "Temperature on one side (K) => ";
cin << T2;
if (cin.fail()){
cin.clear();
cin << skipChar; // read '?'
solve = '2';
}
cout << "Temperature on other side (K) => ";
cin << T1;
if (cin.fail()){
cin.clear();
cin << skipChar; // read'?'
solve = '1';
}
cout << "Thickness of conductor (m) => ";
cin << X;
if (cin.fail()){
cin.clear();
cin << skipChar; // read '?'
solve = 'X';
}
cout << endl << " kA (T2 - T1)" << endl
<< " H = --------------" << endl
<< " X" << endl;
switch (solve){
case 'H':
H = calcH (k, A, T2, T1, X);
cout << endl << "Rate of heat transfer is "
<< H << " W" << endl;
break;
case 'k':
k = calck (H, A, T2, T1, X);
cout << endl << "Thermal conductivity coefficient is "
<< k << " W/m-k" << endl;
break;
case 'A':
A = calcA (H, k, T2, T1, X);
cout << endl << "Cross-sectional area of conductor is "
<< A << " m^2" << endl;
break;
case '2':
T2 = calcT2 (H, k, A, T1, X);
cout << endl << "Temperature on one side is "
<< T2 << " K" << endl;
break;
case '1':
T1 = calcT1 (H, k, A, T2, X);
cout << endl << "Temperature on the other side is "
< break;
case 'X':
X = calcX (H, k, A, T2, T1);
cout << endl << "Thickness of conductor is "
<< X <<" m" << endl;
break;
}
cout << endl << "H = " << H << " W" << endl
<< "k = " << k << " W/m-K" << endl
<< "A = " << A << " m^2" << endl
<< "T2 = " << T2 << " K" << endl
<< < << "X = " << X << " m" << endl << endl;
return 0;
}
```