A stopping potential of 0.50 V is required when a phototube is illuminated with monochromatic light of wavelength 590 nm
Monochromatic light of a different wavelength is now shown on the tube, and the stopping potential is measured to be 2.30 V. What is the wavelength of this new light? (c = 3.00 × 108 m/s, e = - 1.60 × 10-19 C, h = 6.626 × 10-34 J ? s, 1 eV = 1.60 × 10-19 J)
A) 320 nm
B) 300 nm
C) 340 nm
D) 360 nm
E) 410 nm
A
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