Solve the problem.A baseball pitcher throws a baseball with an initial velocity of 125 feet per second at an angle of 20° to the horizontal. The ball leaves the pitcher's hand at a height of 4 feet. Find parametric equations that describe the motion of the ball as a function of time. How long is the ball in the air? When is the ball at its maximum height? What is the maximum height of the ball?
A. x = 117.46t; y = -16t2 + 42.75t + 4;
5.15 sec;
1.336 sec;
232.445 feet
B. x = 117.46t; y = -16t2 + 42.75t + 4;
2.762 sec;
1.336 sec;
32.556 feet
C. x = 117.46t; y = -16t2 + 42.75t + 4;
5.525 sec;
1.336 sec;
28.556 feet
D. x = 117.46t; y = -16t2 + 42.75t + 4;
2.575 sec;
1.336 sec;
3.991 feet
Answer: B
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