Solve.An object that is vertically projected into the air has its height, in feet, above the ground given by s = -16t2 + v0t + s0,where s is the height, in feet, v0 is the initial velocity of the object, in feet per second, t is the time the object is in motion, in seconds, and s0 is the height, in feet, from which the object is projected. A ball is thrown straight up from a rooftop at an initial velocity of 86 feet per second from a height of 100 feet. The ball misses the rooftop on its way down and eventually strikes the ground below. How high above the ground will the ball be 4 seconds after being thrown?
A. 174 ft
B. 188 ft
C. 700 ft
D. 686 ft
Answer: B
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