Determine the probability (assuming normal distribution) that a car would need engine maintenance before 90,000 miles.
What will be an ideal response?
The value 90000 is below the mean value and the z value corresponding to 90000 is determined from
A = 0.3238. Therefore, the probability that a car would need engine maintenance before 90000 miles is 0.5-0.3238 = 0.1762
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