Solve the problem.A projectile is fired from a height of 5.6 feet with an initial velocity of 163 ft/sec at an angle of 43° with the horizontal. The parametric equations for the path of the projectile are x = (163 cos 43°)t, and y = 5.6 + (163 sin 43°)t - 16t2,where x and y are in feet and t is in seconds. Find the height of the projectile after 4 seconds. Round your answer to the nearest tenth of a foot.
A. 386.3 ft
B. 188.7 ft
C. 476.8 ft
D. 194.3 ft
Answer: D
Mathematics
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-
- . . .
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