Provide an appropriate response.If a body of mass m falling from rest under the action of gravity encounters an air resistance proportional to four times the square root of velocity, then the body's velocity t seconds into the fall satisfies the equation: m = mg - 4kv2where k is a constant that depends on the body's aerodynamic properties and the density of the air.Determine the equilibrium, velocity curve, and the terminal velocity for a 170 lb skydiver (mg = 170) with k = 0.005.

Question

A. Equilibrium: v = 




v_terminal = 92.20 ft/sec
B. Equilibrium: v = 


v_terminal = 92.20 ft/sec
C. Equilibrium: v = 

v_terminal = 92.20 ft/sec
D. Equilibrium: v = 

v_terminal = 92.20 ft/sec

Answer 1

Answer: D