Find the integrating factor, the general solution, and the particular solution satisfying the initial condition. y' - 4y = -2e2t ; y(0) = -1

Question

A. integrating factor: e^4t
general solution: y = -2t + Ce^4t
particular solution: y = -2t - e^4t
B. integrating factor: e^-4t
general solution: y = -e^-2t + Ce^4t
particular solution: y = -e^-2t - 2e^4t
C. integrating factor: e^-4t
general solution: y = e^2t + Ce^4t
particular solution: y = e^2t - 2e^4t
D. integrating factor: e^4t
general solution: y = e^6t + Ce^4t
particular solution: y = e^6t - e^4t

Answer 1

Answer: C