Perturbations of planets are due to
A) interplanetary forces.
B) deviations from straight-line paths.
C) uneven masses of planets.
D) none of the above
Answer: A
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An auto accelerates from 7.0 m/s at 0.71 m/s2. It travels a distance of 1.033 km while accelerating
(a) What is the final speed at the end of that displacement? (b) How many seconds did it take to accelerate from 7.0 m/s?
A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular deceleration. What is the tangential velocity of a point 4.0 cm from the center at the time 2.0 seconds from the start?
A. 0.060 m/s B. 0.080 m/s C. 0.10 m/s D. 0.14 m/s E. 0.18 m/s
This graph shows the number of asteroids with different orbital periods. Notice the gap indicated by the downward-pointing black arrow. What does this graph tell us about this gap?
A) There are few if any asteroids at the indicated orbital period of about 4 years. B) There are more asteroids concentrated at the orbital period indicated by the arrow than at any other orbital period. C) Asteroids with an orbital period of about 4 years are all located very close together; so close that collisions occur frequently. D) There are exactly 495 asteroids with an orbital period of 4 years.
Galaxy A is 300 Mpc from Galaxy B. Hubble's Law says that V=H0 x D. About how fast is Galaxy A receding from the perspective of Galaxy B? Use a value of 75 km/s/Mpc for Hubble's constant.
A) 75 km/s B) 15000 km/s C) 30000 km/s D) 225 km/s E) 22500 km/s