Use the frequency distribution to find the mean and the sample standard deviation. Does the data form a normal distribution? Remember: if the data fall within 2% of the empirical rule of 68%, 95%, and 99.7% for one, two, or three standard deviations, respectively, they form a normal distribution.
Weight (lb) Midpointx Frequency f1.5 - 10.5 1210.5 - 19.5 3919.5 - 28.5 12028.5 - 37.5 20737.5 - 46.5 36846.5 - 55.5 34455.5 - 64.5 22264.5 - 73.5 10073.5 - 82.5 3082.5 - 91.5 12
A. The mean is 36 lb. The sample standard deviation is 10.4 lb. The data forms a normal distribution.
B. The mean is 36 lb. The sample standard deviation is 10.4 lb. The data doesn't form a normal distribution.
C. The mean is 46 lb. The sample standard deviation is 14.6 lb. The data doesn't form a normal distribution.
D. The mean is 38 lb. The sample standard deviation is 13.6 lb. The data doesn't form a normal distribution.
E. The mean is 46 lb. The sample standard deviation is 14.6 lb. The data forms a normal distribution.
Answer: E
You might also like to view...
Solve the problem.The time T in seconds for a pendulum of length L feet to make one swing is given by 
How long is a pendulum (to nearest hundredth) if it makes one swing in 1.4 seconds? Use 3.14 for ?.
A. 13.73 ft B. 86.24 ft C. 21.56 ft D. 2.19 ft
Simplify by using the order of operations. Round your answer to the nearest hundredth.45.5 - 2.5 ÷ 3 ? 48.9
A. 0.29 B. 4.75 C. 700.90 D. 2184.20
In a right triangle, the length of the hypotenuse is 13 inches and the length of one of the legs is 12 inches. Find the length of the other leg.
What will be an ideal response?
Simplify.
A. 81 B. 3 C. 9 D. 27