Circular Motion of Charges: A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040 T at a right angle to the field. What is the radius of the proton's resulting orbit? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)

A. 0.080 m
B. 0.11 m
C. 0.14 m
D. 0.17 m


Answer: B

Physics & Space Science

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