In practice a computer spends a fraction of the time performing internal operations as well as memory accesses. Consequently, the effective speedup ratio is reduced, because cache memory has no effect on internal operations. The average time required to execute an instruction can be written


Finternal = fraction of time spent doing internal operations ( 0 to 1)
Fmemory = fraction of time spent doing memory accesses ( 0 to 1)
tcyc = clock cycle time
tc= cache access time expressed in clock cycles
td= delay penalty paid when not accessing cache memory expressed in clock cycles

Computer Science & Information Technology

You might also like to view...

Will my program compile, link, and run if I have the prototype but not the function body? Will it compile, link, and run if I have the function body but not the prototype? Prototype and call, but no function body? Call, function body, but no prototype?

What will be an ideal response?

Computer Science & Information Technology

It is possible to get the OS X to run on a PC

Indicate whether the statement is true or false

Computer Science & Information Technology

Availability describes what percentage of the time the resource or the data is available

Indicate whether the statement is true or false.

Computer Science & Information Technology

A technician needs multiple networks, high speeds, and redundancy on a system. Which of the following configurations should be considered for these requirements? (Select TWO).

A. Routing table B. Next hop C. Port mirroring D. Port monitoring E. VLANs

Computer Science & Information Technology