Solve the problem.The half-life of a certain radioactive substance is 13 years. Suppose that at time t = 0 , there are 20 g of the substance. Then after t years, the number of grams of the substance remaining will be N(t) = 20(1/2)t/26How many grams of the substance will remain after 39 years?
A. 0.88 g
B. 1.77 g
C. 7.07 g
D. 3.54 g
Answer: C
Mathematics
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+ 
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? 
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, ?)
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