Solve. Assume the exercise describes a linear relationship.In 2005, John invested $14,000 in the stock market. By 2010 his investment had grown to $15,400. Find an equation relating time and the value of the investment. If the market continues to grow at the same rate, how much will be in his account in 2016? Give your answer to the nearest dollar.
A. $15,401
B. $17,080
C. $15,681
D. $16,800
Answer: B
Mathematics
You might also like to view...
Factor, if possible.x2 - x - 54
A. (x - 54)(x + 1) B. (x + 6)(x - 9) C. (x - 6)(x + 9) D. Prime polynomial
Mathematics
Expand the expression.(4x + 3)4
A. 256x4 + 864x3 + 768x2 + 432x + 81 B. 256x3 + 768x2 + 864x + 432 C. (16x2 + 12x + 9)4 D. 256x4 + 768x3 + 864x2 + 432x + 81
Mathematics
Solve the problem.Midtown Antiques has found that sales have decreased 4% from last year. Sales this year are $185,996. Find the amount of last year's sales. Round your answer to the nearest dollar.
A. $193,646 B. $193,736 C. $193,746 D. $194,746
Mathematics
Combine and simplify, if possible.-3
+ 4
A. 26
B. -14
C. -26
D. 14
Mathematics