Consider the feasible set shown below that corresponds to a certain linear programming problem. Three of the boundary lines are labeled with their slopes. 
The objective function, x + 2y, assumes its minimum value at what point?
A. A.
B. B.
C. C.
D. D.
E. O.
Answer: B
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You will select a card from three hats. There are 2 cat cards and 1 dog cards in Hat 1, 4 cat, and 3 dog cards in Hat 2, and 5 cat, and 4 dog cards in Hat 3. What is the probability of selecting a cat card from Hat 1, a cat card from Hat 2, and a dog card from Hat 3? ?
A.
?
B.
?
C.
?.08 rounded to the nearest 1/100th.
D.
?.07 rounded to the nearest 1/100th.
E.
?
Find the quotient.
÷ 
A. - 
B. 
C. 
D. -
Match the given function to its graph.1) y = sin 2x2) y = 2 cos x3) y = 2 sin x4) y = cos 2xA B
C D
A. 1A, 2D, 3C, 4B B. 1A, 2C, 3D, 4B C. 1A, 2B, 3C, 4D D. 1B, 2D, 3C, 4A
Evaluate the function for the indicated input and interpret the result.The table lists the number of persons voting in an election by election year and sex, for a small community. 
Let this table be a partial numerical representation of a function f, where 
computes the number of persons who voted in the year x whose sex is y. Evaluate 
Interpret the result.
A. f (1988, Male) - f (1988, Female) = 198 In the year 1988, 198 more men voted than women. B. f (1988, Male) - f (1988, Female) = 198 In the year 1988, 198 more women voted than had voted previously. C. f (1988, Male) - f (1988, Female) = 198 In the year 1988, 198 more men voted than had previously. D. f (1988, Male) - f (1988, Female) = 198 In the year 1988, 198 more men voted than women in 1984.