Calculate the amount of 90% ethanol needed to prepare 400 mL of 50% ethanol, using water as the diluent: ________.
Fill in the blank(s) with the appropriate word(s).
222 mL
Use the alligation method. A total of 50 parts of 90% ethanol are needed, and 40 parts of water are needed, for a total of 90 parts.
400 mL needed ÷ 90 parts = 4.44 mL per part
4.44 mL × 50 = 222 mL of 90% ethanol are needed
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