Which of the following would be a usable IP address to assign to a host in the network 192.168.10.32/28?
A) 192.168.10.39
B) 192.168.10.47
C) 192.168.10.14
D) 192.168.10.54
A
Explanation: A) The correct answer is 192.168.10.39 because the given mask of /28 converts to a value of 255.255.255.240, and subtracting the fourth value from 256 (256 — 240 ) equals 16 (magic number). The multiples of 16 include the values 0, 16, 32, 48, and so on. Using the last value of the IP address given, compare it to your list and take the lowest value; the subnet would be 192.168.10.32. This makes the available host range 33 through 46.
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