Solve the problem.An investment is worth $2864 in 2013. By 2018 it has grown to $4254. Let y be the value of the investment in the year x, where x = 0 represents 2013. Write a linear equation that models the value of the investment in the year x.
A. y = 
x + 2864
B. y = -278x + 5644
C. y = -278x + 2864
D. y = 278x + 2864
Answer: D
Mathematics
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