Use the Principle of Mathematical Induction to show that the statement is true for all natural numbers n.1 ? 7 + 2 ? 7 + 3 ? 7 + . . . + 7n = 

What will be an ideal response?


First we show that the statement is true when n = 1.
 For n = 1, we get 7 =  = 7.
This is a true statement and Condition I is satisfied.

Next, we assume the statement holds for some k. That is,
  is true for some positive integer k.
We need to show that the statement holds for k + 1. That is, we need to show that
 
So we assume that  is true and add the next term,  to both sides of the equation.
1 ? 7 + 2 ? 7 + 3 ? 7 + . . . + 7k + 7(k + 1) =  + 7(k + 1)
 
 
Condition II is satisfied. As a result, the statement is true for all natural numbers n.

Mathematics

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A. (0, -4), (-4, 0) B. (0, 0) C. (0, -4), (0, 4) D. (0, -4), (0, 0), (0, 4)

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A. 3
B. 4
C. 3
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Find the missing factor.35x2 + 16xy - 12y2 = (5x - 2y)( )

A. 6x - 7y B. 6y - 7x C. 7x + 6y D. 7 + 6xy

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Perform the operation. Write the answer as a mixed number. - 4

A. - 3
B. - 2 
C. 2 
D. 3 

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