In the circuit shown below,

(a) Find the equivalent resistances Ra = R3 || R4, Rb = R5 || R6, and Rc = Ra + Rb.

(b) Redraw the circuit consisting of Is, R1, R2, Rc.

(c) Use the current divider rule to find the currents I1, I2, Ic.

(d) Use the current divider rule to find the currents I3, I4, I5, I6.

(e) Find the voltages V1, V2.


















Is=4e-3;

R1=9000;R2=12000;R3=24000;R4=56000;R5=24000;R6=96000;

Ra=P([R3,R4])

Rb=P([R5,R6])

Rc=Ra+Rb

I1=Is/R1/(1/R1+1/R2+1/Rc)

I2=Is/R2/(1/R1+1/R2+1/Rc)

Ic=Is/Rc/(1/R1+1/R2+1/Rc)

I3=Ic/R3/(1/R3+1/R4)

I4=Ic/R4/(1/R3+1/R4)

I5=Ic/R5/(1/R5+1/R6)

I6=Ic/R6/(1/R5+1/R6)

V1=R1*I1

V2=R5*I5

VR3=R3*I3

Vloop=-V1+VR3+V2

Answers:

Ra =

16800

Rb =

19200

Rc =

36000

I1 =

0.002000000000000

I2 =

0.001500000000000

Ic =

5.000000000000000e-04

I3 =

3.500000000000000e-04

I4 =

1.500000000000000e-04

I5 =

4.000000000000001e-04

I6 =

1.000000000000000e-04

V1 =

18

V2 =

9.600000000000001

VR3 =

8.400000000000000

Vloop =

1.776356839400251e-15

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