How many different orders can all the messages be delivered to each process?
Suppose a multicast group currently is participated by two processes: P1 and P2. Suppose P1 multicasts m11 then m12, P2 multicasts m21 then m22.
For P1, m11 must be delivered before m12, but m21 and m22 can be delivered in either order, so the total number of orders that can be delivered to P1 is 4!/(2!) = 12. Similarly, the total number of orders that can be delivered to P1 is also 12.
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