At -12°C, refrigerant R-134a has vf = 0.0007498 m3/kg and vg = 0.1068 m3/kg. 3 kg of a saturated mixture of R-134a at -12oC has a quality of 0.93. Determine the specific volume and the total volume of the R-134a.
Given: vf = 0.0007498 m3/kg; vg = 0.1068 m3/kg; x = 0.93; m = 3.0 kg
What will be an ideal response?
v = x(vg-vf) + vf =0.0994 m3/kg
V = mv = 0.298 m3
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