Translate to a system of three equations, then solve.A object is thrown upward with an initial velocity of v0 from an initial height of h. The height of the object, h, is described by an equation of the form h = at2 + v0t + h0, where h and h0 are in feet and t is in seconds. The table below shows the height for different values of t. Find the values of a, v0, and h0 and write the equation for h. 
A. a = 16, v0 = 150, h0 = 200; h = -16t2 + 150t + 200
B. a = 16, v0 = 200, h0 = 150; h = 16t2 + 200t + 150
C. a = -16, v0 = 150, h0 = 200; h = -16t2 + 150t + 200
D. a = -16, v0 = 200, h0 = 150; h = -16t2 + 200t + 150
Answer: D
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+
+ ...
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?
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A. multiplying; canceling B. adding; multiplying C. multiplying; multiplying D. multiplying; adding
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A.
B.
C.
D.