A series circuit contains a total resistance of 100. If the circuit has three resistors and one of the resistors is 40 , what is the combined resistance of the last two resistors?
a. 60 c. 140
b. 2.5 d. 0.04
ANS: A
According to Kirchhoff's laws regarding series circuits, total resistance is equal to the sum of all resistors in the circuit. If the circuit has three resistors, total resistance = A + B + C. Therefore, 100 = A + B + C. If one resistor is 40 , then 100 = 40 + B + C and the sum of B + C must equal 60 .
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