Solve the initial value problem.
= 4 - 2x, y '(0) = 8, y(0) = 2
A. y = 4x2 + 2x3 + 8x + 2
B. y = 2x2 + 
x3 - 8x - 2
C. y = 2
D. y = 2x2 - 
x3 + 8x + 2
Answer: D
Mathematics
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