Solve. Assume the exercise describes a linear relationship.An investment is worth $2625 in 2006. By 2010 it has grown to $4617. Let y be the value of the investment in the year x, where x = 0 represents 2006. Write a linear equation that models the value of the investment in the year x.
A. y = -498x + 2625
B. y = 498x + 2625
C. y = -498x + 6609
D. y = 
x + 2625
Answer: B
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Solve the problem using the tables below.
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