The autosomal (not X-linked) gene for brachydactyly, short fingers, is dominant to normal finger length. Assume that a female with brachydactyly in the heterozygous condition is married to a man with normal fingers
What is the probability that
(a) their first child will have brachydactyly?
(b) their first two children will have brachydactyly?
(c) their first child will be a brachydactylous girl?
(a) 1/2
(b) 1/2 × 1/2 = 1/4
(c) 1/2 × 1/2 = 1/4
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