Refer to Figure 10.4 and assume that for a pnp transistor the emitter and base currents are IE = 5 mA and IB = 0.2 mA, respectively. The voltage drops across the emitter-base and collector-base junctions are VEB = 0.67 V and VCB = 7.8 V. Find:

a. VCE.

b. The collector current.

c. The total power dissipated in the transistor, defined here as P = VCE IC + VBE IB.





Known quantities:

The magnitude of a pnp transistor's emitter and base current, and the magnitudes of the voltages across the emitter-base and collector-base junctions:


Analysis:

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