Refer to Figure 10.4 and assume that for a pnp transistor the emitter and base currents are IE = 5 mA and IB = 0.2 mA, respectively. The voltage drops across the emitter-base and collector-base junctions are VEB = 0.67 V and VCB = 7.8 V. Find:
a. VCE.
b. The collector current.
c. The total power dissipated in the transistor, defined here as P = VCE IC + VBE IB.
Known quantities:
The magnitude of a pnp transistor's emitter and base current, and the magnitudes of the voltages across the emitter-base and collector-base junctions:
Analysis:
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