Solve the problem. Assume projectile is ideal, launch angle is measured from the horizontal, and launch is over a horizontal surface, unless stated otherwise.Derive the equations x = x0 + (v0 cos ?)t, y = y0 + (v0 sin ?)t - 
gt2by solving the following initial value problem for a vector r in the plane. Differential equation: 
= -gj Initial conditions: r(0) = x0i + y0j 
(0) = v0 cos ?)i + (v0 sin ?)j
What will be an ideal response?
x-coordinate:
= 0, so 
= constant = vo,x = voc os ?
Then, x = 
dt = 
dt = vo cos ? t + xo
y-coordinate:
= -g , so 
= 
dt = 
dt = -gt + vy,o = vo sin ? - gt
y = 
dt = 
dt = vo sin ? t - 
gt2 + yo
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