Solve the problem.The Earth rotates about its pole once every 24 hours. The distance from the pole to a location on Earth 35° north latitude is about 3,243.8 miles. Therefore, a location on Earth at 35° north latitude is spinning on a circle of radius 3,243.8 miles. Compute the linear speed on the surface of the Earth at 35° north latitude.
A. 849 mph
B. 20,381 mph
C. 795 mph
D. 135 mph
Answer: A
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Find all solutions of the equation in the interval [0°, 360°).cos2 ? + 2 cos ? + 1 = 0
A. {180°} B. {360°} C. {45°, 315°} D. {90°, 270°}
The function f is one-to-one. State the domain and the range of f and f-1. Write the domain and range in set-builder notation.f(x) = 
A. f(x): D = 
, R = 
;
f-1(x): D is all real numbers, R = 
B. f(x): D = 
, R = 
;
f-1(x): D = 
, R = 
C. f(x): D = 
, R is all real numbers;
f-1(x): D is all real numbers, R = 
D. f(x): D = 
, R = 
;
f-1(x): D = 
, R = 
Solve the problem.A company's monthly sales, in thousands, is given by S(x, y) = 6x0.3y0.4, where x is the amount spent on newspaper advertising per month in thousands of dollars and y is the amount spent on radio advertising per month in thousands of dollars. Suppose the company currently spends $2000 on newspaper advertising per month and $5000 on radio advertising per month. What would be the effect on sales if the company increases the amount spent on newspaper advertising to $3000, while the amount spent on radio advertising remains constant?
A. Sales would increase by $228.98. B. Sales would increase by $1588.09. C. Sales would decrease by $158.81. D. Sales would increase by $1124.96.
Solve for x.|0.6x - 0.8| ? 1
A. -1.5 ? x ? -1.167 B. -0.333 ? x ? 3 C. 1.167 ? x ? 1.5 D. -3 ? x ? 0.333