Solve the initial value problem.Differential Equation: 
= (4 sec 4t tan 4t) i + 
j + t2kInitial Condition: r(0) = 3i + 
j - 3k
A. r(t) = (csc 4t + 2)i + 
j + 
k
B. r(t) = (sec 4t + 2)i + 
j + 
k
C. r(t) = (sec 4t + 2)i - 
j + 
k
D. r(t) = (csc 4t + 2)i + 
j + (t3 - 3)k
Answer: B
Mathematics
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