Solve the initial value problem for x as a function of t.(2t3 - 2t2 + t - 1) 
= 3, x(2) = 0
A. x = ln 
- 
ln 
+ 
ln 4.5
B. x = ln 
- tan-1 
t - ln 
+ tan-1 2
+ ln 4.5
C. x = ln 
- 
tan-1 
t + 
tan-1 2
D. x = ln 
- 
tan-1 
t - 
ln 
+ 
tan-1 2
+ 
ln 4.5
Answer: D
Mathematics
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