Solve the problem.Two stores sell a certain product. Store A has 37% of the sales, 3% of which are of defective items, and store B has 63% of the sales, 5% of which are of defective items. The difference in defective rates is due to different levels of pre-sale checking of the product. A person receives one of this product as a gift. What is the probability it is defective?
A. 0.022
B. 0.043
C. 0.04
D. 0.4
Answer: B
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Use the Fixed-Point Algorithm with x1 as indicated to solve the equation to five decimal places.x = 2 cos x; x1 = 1
A. 1.0806 B. 1.02987 C. 0.76738 D. No solution
Solve.The average value of a certain type of automobile was $20,460 in 2006 and depreciated to $14,880 in 2011. Let y be the average value of the automobile in the year x, where x = 0 represents 2006. Write a linear equation that relates value y to year x.
A. y = -1116x + 9300
B. y = - 
x - 14880
C. y = -1116x + 14,880
D. y = -1116x + 20,460
Find all the second partial derivatives.f(x, y) = cos xy2
A. 
= -y4 cos xy2; 
= -2x[2xy2 cos(xy2) + sin(xy2)]; 
= 
= -2y[xy2 cos(xy2) + sin(xy2)]
B. 
= - y2 sin xy2; 
= 2y
; 
= 
= 2
C. 
= - y2 sin xy2; 
= 2[ sin (xy2) - 2y2 cos (xy2)]; 
= 
= 2y [sin (xy2) - y2 cos (xy2)]
D. 
= y2 sin xy2; 
= 2[2y2 cos (xy2) - sin (xy2)]; 
= 
= 2y[y2 cos (xy2) - sin (xy2)]
Solve.The power that a resistor must dissipate is jointly proportional to the square of the current flowing through the resistor and the resistance of the resistor. If a resistor needs to dissipate 
of power when 
of current are flowing through the resistor whose resistance is 
find the power that a resistor needs to dissipate when 
of current are
flowing through a resistor whose resistance is 
A. 14 watts
B. 98 watts
C. 126 watts
D. 28 watts