The fruitfly cross shown here analyzes the transmission of two genes on the X chromosome. In the parental generation, the male parent carries mutant alleles for both the white gene (w) and the crossveinless gene (cw)
The female parent carries nonmutant forms of these
genes. A cross between siblings of the F1 generationâ€"a red-eyed, crossveined female and
a red-eyed, crossveined maleâ€"generates F2 progeny. Examine the genotype of the F2
male progeny. Notice that the progeny fall into two groups. Refer to this figure when
answering the following question:
The numbers of male F2 progeny with each of the four observed phenotypes are as follows:
Red-eyed, crossveined = 357
White-eyed, crossveinless = 341
Red-eyed, crossveinless = 52
White-eyed crossveined = 45
What is the map distance between the two genes w and cw?
A. 97
B. 12.2
C. 341
D. 357
E. 13.9
B
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