In the circuit shown below,
(a) Write a mesh equation around mesh 1 by summing the voltage drops around mesh 1.
(b) Write a mesh equation around supermesh formed by meshes 2 and 3 by summing the voltage
drops around supermesh.
(c) Write a constraint equation expressing Is by I2 and I3.
(d) Find I1, I2, and I3 by solving the three equations.
(e) Find the voltages V1, V2.
Vs=9;Is=3e-3;
R1=2000;R2=1500;R3=3000;R4=1000;
syms I1 I2 I3
[I1,I2,I3]=solve(R1*I1+R3*(I1-I3)+R2*(I1-I2),...
-Vs+R2*(I2-I1)+R3*(I3-I1)+R4*I3,...
Is==I3-I2,...
I1,I2,I3)
V2=R4*I3
V1=Vs-R2*(I2-I1)
I1=vpa(I1,7)
I2=vpa(I2,7)
I3=vpa(I3,7)
V1=vpa(V1,7)
V2=vpa(V2,7)
Answers:
I1 =
0.002322581
I2 =
0.001354839
I3 =
0.004354839
V1 =
10.45161
V2 =
4.354839
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