Find the least common denominator (LCD).
, 
A. (x - 5)(x - 2)(x + 6)
B. (x - 2)(x + 6)
C. (x + 5)(x + 2)(x + 6)
D. (x - 5)(x - 2)
Answer: A
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Solve.The distance an object travels after accelerating from an initial velocity is the product of velocity and the time added to one-half of the product of the acceleration and the square of the time. Write an expression for the height h of an object t seconds after being fired straight up into the air with an initial velocity of 288 m/sec. Then write the expression in factored form.[Note: The acceleration of an object fired vertically upwards is -9.8. m/s2]
A. 288t - 4.9t2 = t(288 - 4.9t) B. 288t - 4.9t2 = 4.9t(288 - t) C. 288t - 9.8t2 = t2(288 - 9.8t) D. 288t - 9.8t2 = t(288 - 9.8t)
Solve by graphing.
A. (14, 10) B. (7, 5) C. (5, 7) D. (10, 14)
Solve. x2 - xy + 3y2 = 32x2 - 3xy + 4y2 = 3
A. (-1, 1), (1, -1), (2, 0), (0, -2) B. (2, 0), (0, -2) C. (1, 1), (-1, -1) D. (1, 1), (-1, -1), (2, 0), (0, -2)
Find the exact value of the logarithmic expression without using a calculator. ? 5 ln e7 ?
A. 7 B. 35 C. 5 D. e E. 1