Solve the differential equation subject to the given condition. Note that y(a) denotes the value of y at t = a. 
= - 0.005y, y(-3) = 14
A. y = -0.005e14(t + 3)
B. y = 14e-0.005(t - 3)
C. y = -0.00514(t + 3)
D. y = 14e-0.005(t + 3)
Answer: D
Mathematics
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B. 
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