As the network engineer, you need to configure a server that is on the same subnet as a host that's assigned the IP address 192.168.19.24/28.28. The router has the first available host address. Which of the following IP addresses and masks could you assign to the server in this network?
A) 192.168.19.0 / 255.255.255.0
B) 192.168.19.27 / 255.255.255.240
C) 192.168.19.26 / 255.255.255.248
D) 192.168.19.31 / 255.255.255.248
E) 192.168.19.34 / 255.255.255.240
B
Explanation: B) The correct answer is 192.168.19.27 / 255.255.255.240 because the given mask of /28 converts to 255.255.255.240, and subtracting the fourth value from 256 (256 - 240 ) equals 16 (magic number). The multiples of 16 include the values 16, 32, 48, and so on. Using the last value of the IP address given, compare it to your list and take the lowest value; the subnet would be 192.168.19.16. The valid hosts range would be 192.168.19.17 through 192.168.19.31.
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