Solve the problem.A 7.00-lb weight stretches a certain spring 0.055 ft. With this weight attached, the spring is pulled 7.00 in. longer than its equilibrium length and released. Find the equation of the resulting motion, assuming no damping. (Round numbers to the nearest hundredth.)
A. y = 0.58 cos 24.12t
B. y = 7.00 cos 24.12t
C. y = 7.00 sin 24.12t
D. y = 0.58 sin 24.12t
Answer: A
Mathematics
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